SOLUTION: Find an equation of the line containing the given pair of points. (1/4, -1/2) and (3/4,2).

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Question 246192: Find an equation of the line containing the given pair of points. (1/4, -1/2) and (3/4,2).
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
Our two points are:
(1/4, -1/2) = (x1, y1)
(3/4, 2) = (x2, y2)
We know y = mx + b
.
m = rise/run = change in y divided by change in x
change in y = y2 - y1 = 2 - (-1/2) = 2 + 1/2= 2.5
change in x = x2 - x1 = 3/4 - 1/4 = 1/2 = .5
m = 2.5/.5 = 5
.
We are given the points above, so we can substitute into y=mx+b
2 = 5(3/4) + b
2 = 15/4 + b
2 - 15/4 = b
b = 2 - 15/4 = 8/4 - 15/4 = -7/4 = -1.75
,
We also can use the other equation to find b as a check.
-1/2 = 5(1/4) + b
-.5 = 1.25 + b
-1.75 = b
.
.
We can graph this line:

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