SOLUTION: please help with these 10 problems thanks question 1 when you use a protractor to draw an angle that opens to the right what degress should be on the right question 2 in eve

Question 245935: please help with these 10 problems
thanks
question 1 when you use a protractor to draw an angle that opens to the right what degress should be on the right

question 2 in every polygon that has n sides there are
a n triangles
b n/2 triangles
c 2n triangles
d n- 2 triangles

problem 3 to find the sum of the interior angles of a regular polygon
a n (180)
b 2n (180)
c n/2 (180)
d n-2 (180)

problem 4 each angle in a regular otagon measures
a 120
b 130
c 140
d 135

problem 5 find the ordered pair that is a solution to this system of inequalities y>x+1 y>-x+3
a y>2,3
b y>1,2
c y>4,5
d y>5,6

problem 6 state the oredere pair that satifies the equation 2x-5y=-1
a (2,4/5)
b (0,3/5)
c (1,4/5)
d (1,3/5)
problem 7 a toy designer wants to create a set of toys with a center of gravity. the best choice of concurrnent lines and points to place the center of gravity would be
a the centroid
b the orthocenter
c the incenter
d the circumcenter

problem 8 in an equilateral triangle the inceter is the intersection of
a 3 medians
b 3 perpendicular bisectors
c 3 altitudes
d 3 angle bisectors

problem 9 in an equilateral triangle the cirumcenter is
a on leg a
b on leg b
c on leg c
d the inside of the triangle
problem 10 in an equilateral triangle the centroid is the intersection of
a 3 angle bisectors
b 3 perpendicular bisectrs
c 3 altitudes
d 3 medians
Found 2 solutions by solver91311, JimboP1977:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

No. We don't do entire assignments here. Pick something that is giving you difficulty and ask a question. Show the work you have done so far. We are here to help you learn mathematics, not to do it for you so that you don't have to think for yourself or do any work.

John

Answer by JimboP1977(311) (Show Source): You can put this solution on YOUR website!
Absolutely John!
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