SOLUTION: My problem is 3/2,-3 0,2/5 this involves the y2-y1 x2-x2 I'm having some problems with the fractions.

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Question 244833: My problem is 3/2,-3 0,2/5 this involves the y2-y1
x2-x2
I'm having some problems with the fractions.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note: is the first point . So this means that x%5B1%5D=3%2F2 and y%5B1%5D=-3.
Also, is the second point . So this means that x%5B2%5D=0 and y%5B2%5D=2%2F5.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%282%2F5--3%29%2F%280-3%2F2%29 Plug in y%5B2%5D=2%2F5, y%5B1%5D=-3, x%5B2%5D=0, and x%5B1%5D=3%2F2


m=%2817%2F5%29%2F%280-3%2F2%29 Subtract -3 from 2%2F5 to get 2%2F5--3=2%2F5%2B3=2%2F5%2B15%2F5=%282%2B15%29%2F5=17%2F5


m=%2817%2F5%29%2F%28-3%2F2%29 Subtract 3%2F2 from 0 to get -3%2F2


m=%2817%2F5%29%2A%28-2%2F3%29 Multiply the first fraction by the reciprocal of the second fraction.


m=-34%2F15 Multiply.


So the slope of the line that goes through the points and is m=-34%2F15