SOLUTION: graph y= 2sin(2x - pi) on the interval 0 <= x <= 2pi

Question 234110: graph y= 2sin(2x - pi) on the interval 0 <= x <= 2pi
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Steps to follow:
1-find altitude, period and phase shift
2-On the xy-plane, the period will reveal where to start and end your graph for one cycle
Do you see the number 2 in front of the word sin? That is your altitide.
This means the graph will go up 2 units from the origin and down 2 units from the origin on the y-axis.
To find the period, use P = 2pi divide by the coefficient of x.
The coefficient of x (look inside the parentheses is 2). See it?
So, P = 2pi/2 = pi
Your period for this trig function is pi.
This means that the graph of your trig function will repeat itself every pi units without end to the left and right of the origin on the x-axis.
To find the phase shift, set (2x - pi) between 0 and 2pi and solve for x.
0 ≤ 2x - pi ≤ 2pi
After doing the math, we find out that the phase shift is pi/2.
You now have enough information to graph your trig function.
If this does not make sense, write back.

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