SOLUTION: graph 30x+50y-100=0 3x-15y-30=0

Question 229286: graph 30x+50y-100=0
3x-15y-30=0
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
graph
30x+50y-100=0 or 30x+50y=100
3x-15y-30=0 or 3x-15y=30

Step 1. The graph of the two lines are shown below:

Step 2. The intersection point is (-1,5) or x=-1 and y=5

Step 3. As a check, solve using substitution

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
We'll use substitution. After moving 50*y to the right, we get:
, or . Substitute that
into another equation:
and simplify: So, we know that y=-1. Since , x=5.

Answer: .

which yields the same result with x=5 and y=-1.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV
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