SOLUTION: give the equation of the line that passes thru (0.9,0.3) and parallel to 3x+2y=6, leave your answer in y=mx+b form

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Question 226400: give the equation of the line that passes thru (0.9,0.3) and parallel to 3x+2y=6, leave your answer in y=mx+b form
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
slope-intercept form of the equation of a line is y = mx = b where m is the slope and b is the y-intercept.

equation of 2x + 2y = 6 is the standard form of the equation of a line.

That standard form is ax + by = c

You need to convert that equation to the slope intercept form first.

2x + 2y = 6 is the original equation.
subtract 2x from both sides of the equation to get:
2y = -2x + 6
divide both sides of the equation by 2 to get:
y = -x + 3

your original equation in slope-intercept form is:

y = -x + 3

The slope of your original equation is -1.

Your equation will have the same slope.

take the general slope-intercept form of:

y = mx + b

and replace m with -1 to get:

y = -x + b

now take your points of (x,y) = (.9,.3) and replace x and y in this equation with them.

you get:

y = -x + b becomes:
.3 = -.9 + b
add .9 from both sides of this equation to get:
.3 + .9 = b
simplify to get:
b = 1.2

replace b in the slope-intercept form of your equation to get:

y = -x + 1.2

That should be your equation.

Graph the original equation and your equation to show as follows:

The horizontal line at y = .9 shows you that this occurs on your parallel line at around x = .3