SOLUTION: Can someone help me solve for x?
(2x + 3y) + 3x = -3(y-4x) this is as far as I got
2x + 3y + 3x = -3y + 12x
5x + 3y = -3y + 12x
3y + 3y = 12x - 5x
6y = 7x
Algebra.Com
Question 22622: Can someone help me solve for x?
(2x + 3y) + 3x = -3(y-4x) this is as far as I got
2x + 3y + 3x = -3y + 12x
5x + 3y = -3y + 12x
3y + 3y = 12x - 5x
6y = 7x
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
You almost got it!! Just divide both sides of the equation by the coefficient of x:
so divide both sides by 7:
or
R^2 at SCC-
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