SOLUTION: Can someone help me solve for x? (2x + 3y) + 3x = -3(y-4x) this is as far as I got 2x + 3y + 3x = -3y + 12x 5x + 3y = -3y + 12x 3y + 3y = 12x - 5x 6y = 7x

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Question 22622: Can someone help me solve for x?
(2x + 3y) + 3x = -3(y-4x) this is as far as I got
2x + 3y + 3x = -3y + 12x
5x + 3y = -3y + 12x
3y + 3y = 12x - 5x
6y = 7x






Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
You almost got it!! Just divide both sides of the equation by the coefficient of x:

so divide both sides by 7:

or

R^2 at SCC-

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