SOLUTION: determine the values (write a compound inequality) of x that gives the triangle below a perimeter of no more then 100 and no less than 28. for the
left side of triangle 4(x-3)
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Question 222324: determine the values (write a compound inequality) of x that gives the triangle below a perimeter of no more then 100 and no less than 28. for the
left side of triangle 4(x-3)
right side of triangle 3x
bottom of triangle 5x + 4
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The perimeter of a triangle is the sum of the measures of the three sides, so for your triangle,
 + 3x + 5x + 4)
Simplify:
The perimeter can be no more than 100, so it is less than or equal to 100 and no less than 28, so it is greater than or equal to 28, so:
Add 8 to all three parts of the compound inequality:
Divide all three parts of the compound inequality by 12:
However, we have to change the inequality sign on the low end of the interval. That is because 
. If 
then the measure of the left side of the triangle would be 0, i.e.  = 0)
, and there would be no triangle.
Hence, the final interval for 
is:
John
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