SOLUTION: How do you graph an equation using rise over run?

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Question 22174: How do you graph an equation using rise over run?
Answer by Earlsdon(6098) About Me  (Show Source):
You can put this solution on YOUR website!
Rise over run is the definition of the slope, m, of a line. If your equation is in the slope-intercept form: y+=+mx+%2B+b, the slope is given by m and the y-intercept is given by b.
For example, let's say that you wanted to graph the line whose equation is: y+=+%282%2F3%29x+%2B+4 Remember that you need only two points to define a straight line.
The y-intercept is y=4, so mark a point on the y-axis at y=4.
The slope m is 2/3, so that's rise = 2 and run = 3 and since the sign of m is positive, the slope of the line will be leaning to the right.
Then, starting at the point y=4, go up (rise) 2 and then go right (positive) 3 and mark your second point.
Now join the two points with a straight line and you have your graph.
Here's what it should look like on the graph:
graph%28300%2C200%2C-9%2C9%2C-3%2C7%2C%282%2F3%29x%2B4%29