SOLUTION: Please help me solve the problem For the point slope equation given, state the slope and the point on the graph used in creating the equation. y= 10/7(x-11)

Algebra ->  Graphs -> SOLUTION: Please help me solve the problem For the point slope equation given, state the slope and the point on the graph used in creating the equation. y= 10/7(x-11)      Log On


   

Question 219415: Please help me solve the problem
For the point slope equation given, state the slope and the point on the graph used in creating the equation.
y= 10/7(x-11)
Answer by jsmallt9(3759) About Me  (Show Source):
You can put this solution on YOUR website!
The general point-slope form is:
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29
where m is the slope and (x%5B1%5D, y%5B1%5D) is a point on the line.

In your equation:
y=+%2810%2F7%29%28x-11%29
we can see that the m is 10/7 and that x%5B1%5D is 11. But what is the y%5B1%5D? Your equation has just "y" on the left side. It's "supposed" to be y+-+y%5B1%5D. What would y%5B1%5D have to be in order for y+-+y%5B1%5D to be just "y"? In other words, y minus what number is equal to y? I hope by now that it is obvious that y%5B1%5D+=+0.

So the slope is 10/7 and the point on the graph is (11, 0).