SOLUTION: Give the center and radius of the circle: x^2+y^2-10x+6y+25 I first completed the square: (x^2-10x+25)+(y^2+6y+9)=-25 (x-5)^2+(y-3)^2=-25+25+9 (x-5)+(x-3)=9 (-5,-3) with

Question 214690: Give the center and radius of the circle:
x^2+y^2-10x+6y+25
I first completed the square:
(x^2-10x+25)+(y^2+6y+9)=-25
(x-5)^2+(y-3)^2=-25+25+9
(x-5)+(x-3)=9
(-5,-3) with a radius of 9 but I am not sure if I did that right?!?!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The last equation should be , since factors to . We can take this equation and then rewrite as and to to get

Recall that the general equation of a circle is where (h,k) is the center and 'r' is the radius.

Looking at (which is in the circle form described above), we see that , and (I'm just matching the two forms).

So the center is (5,-3) and the radius is 3 units.

So you just had some minor errors (such as the sign differences and forgetting to take the square root of 9)
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