SOLUTION: Here is the question. Find k if the lines 3x-y=9 and kx+3y=5 are perpendicular. I arranged both equations to equal y; y=3x-9 and y=(5-kx)/3, but I don't know where to go from there
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Question 211350: Here is the question. Find k if the lines 3x-y=9 and kx+3y=5 are perpendicular. I arranged both equations to equal y; y=3x-9 and y=(5-kx)/3, but I don't know where to go from there
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3x-y=9
-y=-3x+9
y=3x+9 ( red line)this line has a slope of 3.
Therefore all perpendicular lines will have a slope=-1/3
kx+3y=5
3y=-kx+5
y=-kx/3+5/3
[-k/3=-1/3]
k=1 ans.
y=-x/3+5/3 (green line)
(graph 200x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions 3x +9 and -x/3 +5/3).
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