SOLUTION: Someone please please please help me find the limits?
I did my best to describe how the graph looks like below:
There is a point that starts at (-1, 0) and it goes down to th
Question 206752: Someone please please please help me find the limits?
I did my best to describe how the graph looks like below:
There is a point that starts at (-1, 0) and it goes down to the south west side for negative infinity
There is a point that has a hole at (-1, 1) and this line goes up to (0, 3).
There is a line that begins at (0, 3) that goes down and reaches 2, since there is an asymptote at x=2, it follows the x=2 asymptote down to negative infinity.
Finally there is a line that goes up to positive infinity following up the x=2 asymptote and goes to positive infinity following the x-axis.
Now please answer these questions:
a) lim x-->0^(+)
b) lim x-->0^(-)
c) lim x-->0
d) x-values where the function is discontinuous
e) x-values where the function is non-differentiable
f) x-values where the slope of the tangent line is zero
g) x-values where the slope of the tangent is undefined Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! There is a point that starts at (-1, 0) and it goes down to the south west side for negative infinity
There is a point that has a hole at (-1, 1) and this line goes up to (0, 3).
There is a line that begins at (0, 3) that goes down and reaches 2, since there is an asymptote at x=2, it follows the x=2 asymptote down to negative infinity.
Finally there is a line that goes up to positive infinity following up the x=2 asymptote and goes to positive infinity following the x-axis.
Now please answer these questions:
a) lim x-->0^(+) = 3
b) lim x-->0^(-) = 3
c) lim x-->0 0
d) x-values where the function is discontinuous: x=-1,x=2
e) x-values where the function is non-differentiable:x=-1,x=0,x=2
f) x-values where the slope of the tangent line is zero: don't see any
g) x-values where the slope of the tangent is undefined:x=-1,x=0,x=2
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Cheers,
Stan H.