SOLUTION: What is the vertex for the parabola whose equation is f(x)=-3(x+12)^2-14?

Question 202496: What is the vertex for the parabola whose equation is f(x)=-3(x+12)^2-14?
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
f(x) =y=-3(x+12)^2 -14
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(y +14) = -3 (x+12)^2
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standard form is,,,,,,(y-k) = A (x-h)^2, with (h,k) as vertex
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from above h= -12,,,and k = -14,,,
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therefore, vertex is ( -12,-14)
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to check,,,A= (-3) which means it is pointed down
.
check on either side of vertex for confirmation
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@ x= -13, y= -3(-13+12)^2 -14,,y= -17,,,which is lower than -14
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@ x=-11, y= -3(-11+12)^2 -14,,,y = -17,,,which again is lower than -14.
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This confirms vertex, and downward pointing of parabola.

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