SOLUTION: can't figure out how to solve problems like 2x+6y=12 finding three ordered pairs, I don't know where to begin
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Question 198017This question is from textbook Intregrated arithmetic and basic algebra
: can't figure out how to solve problems like 2x+6y=12 finding three ordered pairs, I don't know where to begin
This question is from textbook Intregrated arithmetic and basic algebra
Found 2 solutions by solver91311, scott8148:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
What you want to find are three ordered pairs )
so that when you replace 
and 
in the equation with the values from the ordered pair, you have a true statement.
Step 1. Pick a value for . It can be any real number, so pick a small integer -- it makes the arithmetic easier. Zero is a nice round number (so to speak), so let's pick zero for our first try.
Step 2. Substitute the selected number into the equation in place of the .
 + 6y = 12)
Step 3. Solve for :
Step 4. Create your ordered pair from the selected value of and the calculated value of
)
Step 5. Check your work:
 + 6(2) =^? 12)
Checks.
Perform steps 1 through 5 twice more using a new value for each time. Done.
John
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the equation is a straight line --- 1st order in x and y (both to the 1st power)
the 3 "ordered pairs" are just 3 points on the line
pick values for x (or y) and then use the equation to find the corresponding value for the other variable
___ these pairs of values are "ordered"
HINT: zeros are easy to work with
___ and maybe a 1 for y ...
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