# SOLUTION: I need help.... Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x). Thanks

Algebra ->  Algebra  -> Graphs -> SOLUTION: I need help.... Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x). Thanks      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Graphs, graphing equations and inequalities Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Graphs Question 19285: I need help.... Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x). ThanksAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!Graph the polynonmial function P(x)=x^4 + x^3 - 3x^2 -5x -2 and use the zeros (x-intercepts) to find a factorization of P(x). give different values for x ,find P(x) and make a table as follows say x=0,we get P(x)=x^4 + x^3 - 3x^2 -5x -2=0+0-0-0-2=-2 for x=-1,we get P(x)=(-1)^4+(-1)^3-3(-1)^2-5(-1)-2=1-1-3+5-2=0..etc.. x.......0.....-1.........1......etc... P(x)...-2......0........-8 when you plot the graph it looks as follows see where all the curve cuts X axis ..there Y=P(x)=0..those values of x coordinates are the roots of the polynomial.we saw P(x)=0 at x=-1..so x+1 is a factor..proced on this basis to find other factors from the graph.for ex at x=2 the curve cuts x axis and so x=2 is a root and x-2 is a factor