SOLUTION: Find the vertex and intercepts of the function : f(x)=x^2+x-2 This is what I have, is it correct if not, please explain/show. Vertex: (-1 -18) ; Intercepts: (-2,0)(1,0)(0,

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Question 192082This question is from textbook Intermediate Algebra, Applied Approach
: Find the vertex and intercepts of the function : f(x)=x^2+x-2
This is what I have, is it correct if not, please explain/show.
Vertex: (-1 -18) ; Intercepts: (-2,0)(1,0)(0,2)
This question is from textbook Intermediate Algebra, Applied Approach

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
complete the square by adding and subtracting 1/4
:

:
vertex is (-1/2,-9/4)
:
to find y intercept set x to zero y=0^2+0-2=-2 : (0,-2)
:
to find x intercept set y to zero 0=
:

:
x=-2 or 1

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