SOLUTION: Hi, 3x^2 + 3y^2 - 6x - 6 = 0 (describe and sketch the given equation) I believe this is a circle and I've tried "completing the square", but without the b(y) part of the equa

Question 187674This question is from textbook Precalculus
: Hi,
3x^2 + 3y^2 - 6x - 6 = 0 (describe and sketch the given equation)
I believe this is a circle and I've tried "completing the square", but without the b(y) part of the equation, I'm lost. Please help.
Thank you,
Lynn This question is from textbook Precalculus

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3x^2 + 3y^2 - 6x - 6 = 0 (describe and sketch the given equation)
------------------
Divide thru by 3 to get:
x^2 + y^2 - 2x - 2 = 0
---
x^2 - 2x + ? + y^2 = 2
x^2 - 2x + 1 + y^2 = 3
(x-1)^2 + (y-0)^2 = 3
--------------------------------
Circle with center at (1,0) and radius = sqrt(3)
======================================================
Cheers,
Stan H.
RELATED QUESTIONS
Hi, I am trying to find the center and radius of this circle. I thought I had it until I (answered by stanbon)

Hi Guys, really struggling with this question. Given the Cartesian equation of a... (answered by ewatrrr)

hello sir , could u plz tell me how to solve this: √3xsq+2√x-2√3=0... (answered by Alan3354)

Hi, I've tried solving this equation in multiple ways but can't seem to crack it. The... (answered by MathLover1,josgarithmetic,greenestamps)

Hi! Given that x^2-14x+a=(x+b)^2 for all values of x, find the value of a and the... (answered by reviewermath,Okeke_Christian)

16x^2-6x+6=0 For the equation, state the value of the discriminant and then describe the (answered by nerdybill,Alan3354,richwmiller)

one question: about finding center and radius (circle graph) : {{{ 3x^2 + 3y^2 - 6x... (answered by stanbon,scott8148,Earlsdon)

find the radius and centre of a circle with equation... (answered by Edwin McCravy)

This section is about the square root property and completing the square. x^2-6x+9=36 (answered by Alan3354)