SOLUTION: Determine whether the graphs of the equations are parallel lines, perpendicular lines, or neither.
3x - 8y = -18
32x + 12y = -18
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Question 173186This question is from textbook Introductory Algebra
: Determine whether the graphs of the equations are parallel lines, perpendicular lines, or neither.
3x - 8y = -18
32x + 12y = -18
This question is from textbook Introductory Algebra
Found 2 solutions by Mathtut, Alan3354:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
re write these in y=mx+b forms......parallel have equal slopes and perpendicular have negative inverses
:
8y=3x+18--->y=(3/8)x+9/4....so a slope of 3/8
:
12y=-32x-18---->y=-8/3x-3/2...so a slope of -8/3
:
when negative inverses are multiplied they equal -1
:
3/8(-8/3)=-1.
:
therefore the two lines are perpendicular
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Determine whether the graphs of the equations are parallel lines, perpendicular lines, or neither.
3x - 8y = -18
32x + 12y = -18
---------------
Find the slope, m, of both by putting them into slope-intercept form
3x - 8y = -18
8y = 3x + 18
y = (3/8)x + 9/4
m1 = 3/8
--------
32x + 12y = -18
12y = -32x - 18
6y = -16x - 9
y = (-8/3)x - 3/2
m2 = -8/3
That's the negative inverse of m1, so they're perpendicular
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