SOLUTION: find the vertex and the intercepts of the parabola given below and sketch its graph
F(x)=2(x+1)^2-8
Algebra.Com
Question 172410: find the vertex and the intercepts of the parabola given below and sketch its graph
F(x)=2(x+1)^2-8
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
F(x)=2(x+1)^2-8
Vertex: (-1,-8)
X-intercepts: (1,0) and (-3,0)
RELATED QUESTIONS
Find the vertex and intercepts for each parabola, and sketch its graph.
y= -x^2 -3x -... (answered by stanbon)
Identify the vertex, axis of symmetry , y-intercept, x-intercepts, and opening of each... (answered by josgarithmetic)
Given the quadratic function:
f(x) = -1/2x^2-3x+5/2
a. Determine whether the parabola (answered by MathLover1)
Sketch the graph of f(x)=x^2-x-6 include all intercepts and the... (answered by ankor@dixie-net.com)
Find the vertex and intercepts for the parabola. Sketch the graph.... (answered by jim_thompson5910)
Find the vertex and intercepts for the parabola g(x)=x^2+x-6 Sketch the... (answered by solver91311)
Sketch the graph of f(x) = x^2-6x +8. Label all x-intercept, y-intercepts
and the... (answered by jim_thompson5910)
Find the vertex and intercepts for h(x)= -x^2-2x+8 and sketch the... (answered by jim_thompson5910)
find the vertex and intercepts for each parabola. sketch the graph... (answered by venugopalramana)