SOLUTION: Where is the vertex of the graph of y=x^2-5. (resubmitted the first person that answered this didn't give the answer)

Question 1709: Where is the vertex of the graph of y=x^2-5. (resubmitted the first person that answered this didn't give the answer)
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
quadratics are symmetric about the minimum or maximum point...their shape is either a U-shape (for a positive x^2 term) or is n-shaped (for a negative x^2 term).
The beauty and ease of finding a quadratic is "fun".
just pick some "obvious" points...like
1. when x=0, then y=-5
2. when y=0, then , so x HAS 2 SOLUTIONS....+ and -.
So, we can instantly sketch the graph, and as the curve crosses the x-axis at the "same" point on both side of the y-axis, then it is a symmetric shape on the y-axis...so, the minimum point is at y=-5

cheers
Jon.
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