# SOLUTION: The length of a rectangle is 3 m longer than its width. If the perimeter of the rectangle is 38 m find its area

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 Click here to see ALL problems on Graphs Question 163860: The length of a rectangle is 3 m longer than its width. If the perimeter of the rectangle is 38 m find its areaFound 2 solutions by midwood_trail, nerdybill:Answer by midwood_trail(310)   (Show Source): You can put this solution on YOUR website!The length of a rectangle is 3 m longer than its width. If the perimeter of the rectangle is 38 m. Find its area. Let width = x Let length = x + 3 The formula to find the perimeter of a rectangle is given to be: P = 2L + 2W The perimeter is 38 m. 38 = 2(x + 3) + 2(x) 38 = 2x + 6 + 2x 38 = 4x + 6 38 - 6 = 4x 32 = 4x 32/4 = x 8 = x I just found x to be 8. We replace x and x + 3 with 8 and simplify. Width = x = 8 m Length = x + 3 = 8 + 3 = 11 m The width is 8 m and the length is 11 m. ============================================= However, the question is asking for the area. Since we now know the width and length, we can use the formula for finding the area of a rectangle, which is A = LW. Area = 11 m times 8 m Area = 88m^2 We need to place a (^2) at the end of each area question because area is measured in squared units. The final answer is: Area = 88m^2....This is read: "eighty-eight meters squared." Did you follow? Answer by nerdybill(6959)   (Show Source): You can put this solution on YOUR website!Let x = width then because "length of a rectangle is 3 m longer than its width" x+3 = length . Perimeter of any rectangle: 2(width + length) . so: 38 = 2(x + x+3) 38 = 2(2x+3) 38 = 4x+6 32 = 4x 8 m = x (width) . length: x+3 = 8+3 = 11 m (length) . Area of any rectangle: width * length = 8 * 11 = 88 square meters (answer)