SOLUTION: find the equation of the line that contains point (8,-1) and is perpedicular to the line y= 1/4x + 3
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Question 159241: find the equation of the line that contains point (8,-1) and is perpedicular to the line y= 1/4x + 3
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(8,-1)
Y=X/4+3 THIS LINE HAS A SLOPE (m)=1/4.
THE PERPENDICULAR LINE WILL HAVE A SLOPE=4.
-1=4*8+b
b=-1-32
b=-33
THUS THE LINE EQUATION FOR THE LINE THROUGH (8,-1) WITH A SLOPE=4 IS:
Y=4X-33.
(graph 300x200 pixels, x from -6 to 10, y from -40 to 10, 4x -33).
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