SOLUTION: Find the x-intercepts
y=x^2-4x-32
Make y=0 and factor
x^2-4x-32=0
(x-8)(x+4)
Set each one to zero
x-8=0
so x=8
x+4 = 0
so x= -4
Algebra.Com
Question 157718: Find the x-intercepts
y=x^2-4x-32
Make y=0 and factor
x^2-4x-32=0
(x-8)(x+4)
Set each one to zero
x-8=0
so x=8
x+4 = 0
so x= -4
Answer by sassycarrie(1) (Show Source): You can put this solution on YOUR website!
Make y=0 and factor
x^2-4x-32=0
(x-8)(x+4)
Set each one to zero
x-8=0
so x=8
x+4 = 0
so x= -4
RELATED QUESTIONS
Find the x- and y-intercepts. If no x-intercepts exist, state so.
f(x) = x^2 - 5x - 24
(answered by checkley77)
X^2 + 4x... (answered by josmiceli)
Find the x-intercepts.
y = x^2 - 4x -... (answered by vleith,jojo14344)
N =4; -4(⅓), and 2 +3i are zeros; f(1) = 100
1)Since 32+3i are zeros. Conjugate... (answered by greenestamps)
If I have the quadratic function, f(x)= (x^2)-x-12, and I want to find the x-intercept, I (answered by josmiceli,MathTherapy)
The Fundamental Theorem of Algebra
Use the given zero to find the remaining zeros of... (answered by jim_thompson5910,vleith,solver91311)
find the x-intercepts nad y-intercepts for the given circle?
(x^2)+(y^2)-4x-6y+4=0... (answered by jim_thompson5910)
sketch the graph y=x(x-3)(x^2-1) finding additional points to sketch on the graph.
I... (answered by oberobic)
Find the domain of the function.
h(x) = ln[(x^2)/(x-4)]
What I have tried on the... (answered by solver91311)