SOLUTION: Thanks again for your help in advance. I need to double check my work. I have to write these points in standard form. The points are (-4,2) and (2,-3). I came up with -5a-6b=8.

Question 151495This question is from textbook college algebra
: Thanks again for your help in advance. I need to double check my work. I have to write these points in standard form. The points are (-4,2) and (2,-3). I came up with -5a-6b=8. Do I need to multply with negative 1 to get rid of the -5a??? This question is from textbook college algebra

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Start with the slope formula.

Plug in , , , , ,

Subtract from to get

Subtract from to get

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Add 2 to both sides.

Combine like terms. note: If you need help with fractions, check out this solver.

Simplify

Multiply every term by the LCD 6 to clear the fractions.

Add to both sides.

------------------------------

Answer:

So the equation in standard form that goes through the points (-4,2) and (2,-3) is

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write these points in standard form. The points are (-4,2) and (2,-3). I came up with -5a-6b=8. Do I need to multply with negative 1
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That is your option.
You could write it as 5a+6b = -8 or you could leave it the way you have it.
=====================
Cheers,
Stan H.
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