SOLUTION: Hello I am trying to go back to school I have never liked math. Now that I need to take a test to enter college I am confused I have the THEA guide book. But they really don't exp

Question 15047: Hello
I am trying to go back to school I have never liked math. Now that I need to take a test to enter college I am confused I have the THEA guide book. But they really don't explain to well the problems. Anyways I am trying to figure this out 2x+3y=6 I need to graph but first I need to solve for x and then solve for Y. Please I hope you can help me!!!!
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
I'm not familiar with the THEA guide book, but when you are graphing an equation like 2x + 3y = 6, I can't imagine why you would want to solve for x. Solving for y is a nice idea, but I don't think that is the easiest way to graph this equation.

Nevertheless, solve for y by adding -2x from both sides:
2x + 3y = 6
2x-2x + 3y = -2x + 6
3y = -2x + 6

Next, divide both sides by 3 in order to solve for y.
3y= -2x + 6

What this means is the the y intercept is 2, and the slope (steepness!) of the line is -2/3.

Start with an xy graph, and go up two units on the y-axis and put a point. Next, with your pencil on this point on the y axis, measure off the slope which is a rise of -2 followed by a run of 3. This means from the point you made at y=2 on the y-axis, count DOWN 2 units, and go RIGHT 3 units, and put another point. Then connect the points with a line, and extend the line in both directions. The result should look like this:

R^2 at SCC

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