SOLUTION: Hope someone can help me with these
a. Marika is a salesperson who must decide between two monthly income options:
Option 1: Salary of $1412 per month, plus 10% of month
Algebra.Com
Question 150402: Hope someone can help me with these
a. Marika is a salesperson who must decide between two monthly income options:
Option 1: Salary of $1412 per month, plus 10% of monthly sales
or Option 2: Salary of $2000 per month, plus 6% of monthly sales
What must the monthly sales amount be so that Option 1 is a better choice for Marika than Option 2?
Show all your calculations. (this is an example of linear inequality)
b. Solve and check the solutions.
2/x+2/x+1=3x-1/x^2-1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2/x +2/(x+1)= (3x-1)/(x^2-1)
LCM = x(x+1)(x-1)
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Multiply thru by the LCM to get:
2(x^2-1) + 2x(x-1) = (3x-1)x
Rearrange:
2x^2 - 2 + 2x^2 - 2x = 3x^2 -x
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Simplify:
x^2-x-2 = 0
(x-2)(x+1) = 0
x = 2 or x = -1
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x cannot be -1 because x+1 is in the denominator.
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Final Answer: x = 2
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Cheers,
Stan H.
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Cheers,
Stan H.
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