SOLUTION: 13. (8 pts) If a projectile is launched from a platform 40 feet high with an initial velocity of 96 feet per second, then the height of the projectile at t seconds is given by s

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Question 150020: 13. (8 pts) If a projectile is launched from a platform 40 feet high with an initial velocity of 96 feet per second, then the height of the projectile at t seconds is given by
s(t) = –16t^2 + 96t + 40 feet.
(i) At what time does the projectile attain its maximum height? Show some work.






(ii) What is the maximum height attained by the projectile? Show some work.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
# 13

In order to find the time it takes to reach the max height, use this formula:

Start with the given formula.


From , we can see that , , and .


Plug in and .


Multiply 2 and to get .


Divide.


So it takes 3 seconds for the projectile to attain its maximum height.

-------------------------

ii)

To find the max height, simply plug the time into the equation



Start with the given equation.


Plug in .


Square to get .


Multiply and to get .


Multiply and to get .


Combine like terms.


So the max height is 184 feet.

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