SOLUTION: 13. (8 pts) If a projectile is launched from a platform 40 feet high with an initial velocity of 96 feet per second, then the height of the projectile at t seconds is given by
s
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Question 150020: 13. (8 pts) If a projectile is launched from a platform 40 feet high with an initial velocity of 96 feet per second, then the height of the projectile at t seconds is given by
s(t) = –16t^2 + 96t + 40 feet.
(i) At what time does the projectile attain its maximum height? Show some work.
(ii) What is the maximum height attained by the projectile? Show some work.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 13
In order to find the time it takes to reach the max height, use this formula:
Start with the given formula.
From , we can see that , , and .
Plug in and .
Multiply 2 and to get .
Divide.
So it takes 3 seconds for the projectile to attain its maximum height.
-------------------------
ii)
To find the max height, simply plug the time into the equation
Start with the given equation.
Plug in .
Square to get .
Multiply and to get .
Multiply and to get .
Combine like terms.
So the max height is 184 feet.
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