# SOLUTION: hope someone could help me with this Suppose a farmer has 160 feet of fencing to make a rectangular barnyard enclosure. If the enclosure is x feet long, express the area A of th

Algebra ->  Algebra  -> Graphs -> SOLUTION: hope someone could help me with this Suppose a farmer has 160 feet of fencing to make a rectangular barnyard enclosure. If the enclosure is x feet long, express the area A of th      Log On

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 Click here to see ALL problems on Graphs Question 146433: hope someone could help me with this Suppose a farmer has 160 feet of fencing to make a rectangular barnyard enclosure. If the enclosure is x feet long, express the area A of the enclosure as a function of the length. Give an answer by describing your solution. The solution is one of the following: 1. A(x) = x^2 – 40x 2. B. A(x)= square root 25,600-x^2 3. A(x) = 160x – x^2 4. A(x) = 80x – x^2 Which one do you think is correct? show your work Answer by nerdybill(6962)   (Show Source): You can put this solution on YOUR website!Since, perimeter is: L+L+W+W or 2(L+W) The problem GAVE us the length as x. 2(x+W) . Since the problem told us that the total length of fencing is 160 feet we have: 160 = 2(x+W) Solving for W: 80 = x+W 80 - x = W . Well, we all know that the area of a rectangle is length*width we get: x(80 - x) = 80x - x^2