SOLUTION: Here is my "domain" problem if it makes any sense: Find domain of the function y=2sqrt of 4x+10 Teresa M.

Question 142579: Here is my "domain" problem if it makes any sense:

Find domain of the function y=2sqrt of 4x+10
Teresa M.
Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression

Remember you cannot take the square root of a negative value. So that means the argument must be greater than or equal to zero

Set the inner expression greater than or equal to zero

Subtract 10 from both sides

Combine like terms on the right side

Divide both sides by 4 to isolate x

Reduce

So that means x must be greater than or equal to in order for x to be in the domain

So the domain in set-builder notation is

So here is the domain in interval notation: [,)

Notice if we graph , we get
notice how the graph never crosses the line . So this graphically verifies our answer.

and we can see that x must be greater than or equal to in order to lie on the graph

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the domain means allowable values of x __ values that don't result in undefined or imaginary quantities

in this case, the argument of the square root (4x+10) must not be negative

4x+10>=0 __ 4x>=-10 __ x>=-2.5

the domain is all real numbers greater than or equal to -2.5
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