SOLUTION: Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8). Any help with this would be appreciated. Thank you in advance.

Question 142355: Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8). Any help with this would be appreciated. Thank you in advance.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the length of the side parallel to the x-axis is the difference in the x's when the y is constant
__ similarly with the side parallel to the y-axis

x-length __ -0.1-(-7.9) __ 7.8

y-length __ 6.8-(-3.4) __ 10.2

area is 7.8*10.2 __ 79.56
RELATED QUESTIONS
how would this be solved : 1)Find the area of a rectangle if three of its corners are... (answered by scott8148)

Hi all, I am struggling a bit with the following matrices problem. I need to find the... (answered by jsmallt9)

hi sir i got a lottary series question.i am provide some data can you please help me to... (answered by ikleyn)

If (3, 1) and (6, 4) are the coordinates of two corners of a square, which of the... (answered by ikleyn,greenestamps)

Calculate the area of the triangle with the following vertices: 6. (-3, -3), (0, -3), (answered by Alan3354)

1. A rectangular room has a length of 12 feet, a width of 14 feet, and a height of 8... (answered by Fombitz)

Find the area of a parallelogram with vertices (0, 0), (3, 3), (4, 6), and (7, 9) (answered by CubeyThePenguin,ikleyn)

if x=2/3 is a root of 6x^2+kx-2=0. find the valie of k and the other root 2. solve (answered by ikleyn)