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Start with the given inequality

Set the denominator equal to zero

Subtract 3 from both sides

Combine like terms on the right side
So the vertical asymptote is

. This is one critical value

Start with the given equation

Plug in

Solve for x
So our critical values are

and
Now set up a number line and plot the critical values on the number line
So let's pick some test points that are near the critical values and evaluate them.
Let's pick a test value that is less than

(notice how it's to the left of the leftmost endpoint):
So let's pick

Start with the given inequality

Plug in

Evaluate and simplify the left side
Since the inequality is false, this means that the interval does
not work. So this interval is
not in our solution set and we can ignore it.
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Let's pick a test value that is in between

and

:
So let's pick

Start with the given inequality

Plug in

Evaluate and simplify the left side
Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is
(
)
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Let's pick a test value that is greater than

(notice how it's to the right of the rightmost endpoint):
So let's pick

Start with the given inequality

Plug in

Evaluate and simplify the left side
Since the inequality is false, this means that the interval does
not work. So this interval is
not in our solution set and we can ignore it.
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Summary:
So the solution in interval notation is:
(
)
And the graph of this solution set looks like this