SOLUTION: Your help is appreciated.
Convert equation of the parabola y = -6x^2-6x to standard form and then find the product a x h x k.
Thank you.
Algebra.Com
Question 13406: Your help is appreciated.
Convert equation of the parabola y = -6x^2-6x to standard form and then find the product a x h x k.
Thank you.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
The "standard" form you need for this problem is:
You can get your equation into this form by "completing the square".
Starting with your equation, factor a (-6), then complete the square in the x-terms:
Factor -6
Complete the square in x by adding the square of half the x-term (1/2)^2 = 1/4 but don't forget that this is multiplied by -6 so you must add -6(1/4)= -3/2 to the other side as well.
Factor the parentheses and add 3/2 to both sides.
Now compare this with the "standard" form:
and you can see that:
a = -6, h = -(1/2), and k = 3/2
So, to finish the solution to your problem:
= 9/2 = 4.5
RELATED QUESTIONS
{{{Convert equation of the parabola y=-6^2-6x to standard form and then find the product... (answered by stanbon)
Convert the equation to standard form by completing the square on x or y. Then find the... (answered by scott8148,terasse jade)
Given y = x 2 + 6x − 1, complete the square and convert the equation to y =... (answered by ewatrrr)
The Standard form of the equation of a parabola is y=x^2-6x+14. What is the vertex form... (answered by ewatrrr)
convert the equation to standard form by completing the square on x or y. then find the... (answered by josgarithmetic)
Write the equation of a circle in standard form, then find the center and radius of the... (answered by meetkisai)
Convert the equation to standard form by completing the square... (answered by MathLover1)
Convert each equation to the standard form of conic section
y^2+6y-x=0
x^2-y^2-6x+13=0
(answered by ewatrrr)
Please show me how to put this equation of a parabola into standard form:... (answered by josgarithmetic)