SOLUTION: Factor {{{s^2+18s+81}}}

Algebra.Com
Question 132112: Factor
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Looking at we can see that the first term is and the last term is where the coefficients are 1 and 81 respectively.

Now multiply the first coefficient 1 and the last coefficient 81 to get 81. Now what two numbers multiply to 81 and add to the middle coefficient 18? Let's list all of the factors of 81:



Factors of 81:
1,3,9,27

-1,-3,-9,-27 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 81
1*81
3*27
9*9
(-1)*(-81)
(-3)*(-27)
(-9)*(-9)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 18

First NumberSecond NumberSum
1811+81=82
3273+27=30
999+9=18
-1-81-1+(-81)=-82
-3-27-3+(-27)=-30
-9-9-9+(-9)=-18



From this list we can see that 9 and 9 add up to 18 and multiply to 81


Now looking at the expression , replace with (notice adds up to . So it is equivalent to )




Now let's factor by grouping:


Group like terms


Factor out the GCF of out of the first group. Factor out the GCF of out of the second group


Since we have a common term of , we can combine like terms

So factors to


So this also means that factors to (since is equivalent to )


note: is equivalent to since the term occurs twice. So also factors to



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Answer:
So factors to

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