SOLUTION: I ahve a worksheet that I am having trouble with. It says: Find the equation of the line in the graph. On the graph it gives the point (0,3). The sine drawn seems to cross the x

Question 129779This question is from textbook algebra concepts and applications
: I ahve a worksheet that I am having trouble with. It says:
Find the equation of the line in the graph. On the graph it gives the point (0,3). The sine drawn seems to cross the x-axis at (-3,0).
I am totally stumped. Can you please help?
Thanks This question is from textbook algebra concepts and applications

Found 2 solutions by checkley71, solver91311:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(Y2-Y1)/(X2-X1)
(0-3)/(-3-0)
-3/-3=1 IS THE SLOPE.
NOW USING THE LINE EQUATION Y=mX+b & A SET OF (X,Y) VALUES WE SOLVE FOR THE Y INTERCEPT(b).
3=1*0+b
b=3 THE Y INTERCEPT.
THUS THE EQUATION OF THIS LINE IS:
Y=X+3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Well, if you are sure about that second point, you can use the two-point form of the line:

Lets say that is (0,3) and is (-3,0). (It doesn't matter which point you call 1 and which you call 2 as long as you keep it consistent.) That means that:

,
,
, and
.

Just plug in the numbers and do the arithmetic:

If the graph you are working with looks like this, then we have it pretty close anyway.

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