SOLUTION: Given the parabola y=x^2-6x-7, answer the following questions: what is its x-intercept? Find its y-intercept. Graph the parabola.

Question 128351: Given the parabola y=x^2-6x-7, answer the following questions:
what is its x-intercept? Find its y-intercept. Graph the parabola.
Found 2 solutions by jim_thompson5910, chitra:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First let's find the x-intercept(s)

Start with the given equation

To find the x-intercept, let y=0

Plug in

Factor the right side (note: if you need help with factoring, check out this solver)

Now set each factor equal to zero:
or

or Now solve for x in each case

So the x-intercepts are (-1,0) and (7,0)

-----------------------------------------

Now let's find the y-intercept

Start with the given equation

To find the y-intercept, let x=0

Plug in

Raise 0 to the 2nd power to get 0

Multiply 1 and 0 to get 0

Multiply 6 and 0 to get 0

Subtract 0 from 0 to get 0

Subtract 7 from 0 to get -7

So when , we have

So the y-intercept is (0,-7)

If we graph the parabola, we get

Graph of

We can see that the x-intercepts are (-1,0) and (7,0) and that the y-intercept is (0,-7). So this verifies our answer.
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
The given conic is:

To find the x-intercept put y = 0

(x + 1)(x - 7) = 0

==> x = -1 or x = 7

these are 2 x - intercepts

To find the y- intercept put x = 0

==> y = 0 - 6(0) - 7

==> y = -7

This is the one y intercept.

Graph looks this way:

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