SOLUTION:
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?
please help
Algebra.Com
Question 127046:
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?
please help
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.10x+.01(31,000-x)=1390
.10x+310-.01x=1390
.09x=1390-310
.09x=1080
x=1080/.09
x=12,000 answer for the amount invested @ 10%.
31,000-12,000=19,000 amount invested @ 1%.
PROOF:
.10*12000+.01*19000=1390
1200+190=1390
1390=1390
RELATED QUESTIONS
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of... (answered by checkley75)
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of... (answered by Earlsdon)
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of... (answered by josmiceli)
Janet invested $29,000, part at 12% and part at 14%. If the total interest at the end of (answered by Earlsdon)
Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of... (answered by scott8148)
Janet invested $13,000, part at 13% and part at 6%. If the total interest at the end of... (answered by marcsam823)
Janet invested $26,000, part at 6% and part at 3%. If the total interest at the end of... (answered by rfer)
Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of... (answered by drk)
Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of... (answered by stanbon)