SOLUTION: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate?

SOLUTION: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate?

Algebra.Com

Question 126199: Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of the year is $660, how much did he invest at each rate?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.05x+.03(18000-x)=660
.05x+540-.03x=660
.02x=660-540
.02x=120
x=120/.02
x=6000 amount invested @ 5%.
18000-6000=12000 invested @ 3%.
proof:
.05*6000+.03*12000=660
300+360=660
660=660

RELATED QUESTIONS
Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of... (answered by Nate)

Angus invested 18,000, part at 3% and part at 5%. If the total interest at the end of the (answered by checkley71)

Angus invested $18,000, part at 3% and part at 5%. If the total interest at the end of... (answered by Edwin McCravy,checkley75,tutorcecilia)

Angus invested $18000, part at 3% and part at 5%. If the total interest at the end of the (answered by checkley71)

Angus invested $18000, part at 3% and part at 5%. If the total interest at the end of the (answered by oscargut)

I am in need of help with this word problem. Angus invested $22,000, part at 3% and... (answered by stanbon)

Colin invested $24,000, part at 18% and part at 16%. If the total interest at the end of... (answered by checkley71,Nate)

Jon invested $21,000, part at 18% and part at 8%. If the total interest at the end of the (answered by checkley75)

Bob invested $21,000, part at 18% and part at 8%. If the total interest at the end of... (answered by elima)