SOLUTION: can someone check this i'm really lost i thought i had it and now i dont think i do. Solve the system by graphing x+y=3,x+y=-1 x+y=-1 x-x+y=-1-x y=-1-x y=-1-(3-y) y=-4y

Question 122767: can someone check this i'm really lost i thought i had it and now i dont think i do. Solve the system by graphing x+y=3,x+y=-1
x+y=-1
x-x+y=-1-x
y=-1-x
y=-1-(3-y)
y=-4y
x=3-(4y)
x=-1

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given system of equations:

In order to graph these equations, we need to solve for y for each equation.

So let's solve for y on the first equation

Start with the given equation

Subtract from both sides

Rearrange the equation

Divide both sides by

Break up the fraction

Reduce

Now lets graph (note: if you need help with graphing, check out this solver)

Graph of

So let's solve for y on the second equation

Start with the given equation

Subtract from both sides

Rearrange the equation

Divide both sides by

Break up the fraction

Reduce

Now lets add the graph of to our first plot to get:

Graph of (red) and (green)

From the graph, we can see that the two lines are parallel and will never intersect. So there are no solutions and the system is inconsistent.
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