SOLUTION: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far. 2x + 4y + 1 = 0 4y = 2x

SOLUTION: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far. 2x + 4y + 1 = 0 4y = 2x - 1 /4 /4 /4 y = 2/4x -1/4 y = 1/2

Question 122153: I am stuck on this linear equation. I also need to find the rise over run too. This is what I have so far.

2x + 4y + 1 = 0
4y = 2x - 1
/4 /4 /4
y = 2/4x -1/4
y = 1/2x -1/4

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You made a mistake in converting to slope-intercept form

"4y = 2x - 1" <--- In this step, it should be -2x since you subtract 2x from both sides

So the equation in slope-intercept form is

Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is

Since this tells us that the y-intercept is

.Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

Also, because the slope is , this means:

which shows us that the rise is -1 and the run is 2. This means that to go from point to point, we can go down 1 and over 2

So starting at

, go down 1 unit

and to the right 2 units to get to the next point

Now draw a line through these points to graph

So this is the graph of through the points

and

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