SOLUTION: How would I graph the following equations:
(1) y = x - 2
(2) y = x + 2
(3) y = -x - 2
(4) y = -x + 2
I appreciate your help!!
Algebra.Com
Question 121151: How would I graph the following equations:
(1) y = x - 2
(2) y = x + 2
(3) y = -x - 2
(4) y = -x + 2
I appreciate your help!!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started
#1
Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is
Since this tells us that the y-intercept is
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is , this means:
which shows us that the rise is 1 and the run is 1. This means that to go from point to point, we can go up 1 and over 1
So starting at
, go up 1 unit
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
So this is the graph of through the points
and
#2
Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is
Since this tells us that the y-intercept is
.Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is , this means:
which shows us that the rise is 1 and the run is 1. This means that to go from point to point, we can go up 1 and over 1
So starting at
, go up 1 unit
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
So this is the graph of through the points
and
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