SOLUTION: find the axis of symmetry for this function: g(x)=(x^2/2)+4x+6 Vertex formula: -b/2a My Attempts: 1.) a= 1/2 b=4 c=6 AOS: -(4)/2(1/2) = -4 2.) 1/2(x^2+8x)+6 1/2(x^2+8x

Question 1206454: find the axis of symmetry for this function:
g(x)=(x^2/2)+4x+6
Vertex formula: -b/2a
My Attempts:
1.) a= 1/2 b=4 c=6
AOS: -(4)/2(1/2) = -4
2.) 1/2(x^2+8x)+6
1/2(x^2+8x-?+?)+6
I am not sure what to place here when using the factoring route. Apparently the vertex should be (-1,11/2) but I am not sure how they got that since I struggle with factoring.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
----------------------
2.)
1/2(x^2+8x)+6
1/2(x^2+8x-?+?)+6
----------------------

---------not the same function as your g(x).

Axis of Symmetry,

Without performing the algebra steps, vertex looks like (-4,-2).

The algebraic steps you would want would be equivalent to this:

That now in vertex form.
----------read vertex directly from the expression:
(-4,-2)
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