SOLUTION: How do I find the y-intercept for -x + 3y = 15?

Question 120501: How do I find the y-intercept for -x + 3y = 15?
Found 2 solutions by tutor_paul, bucky:
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!
How do I find the y-intercept for -x + 3y = 15?
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First, put the equation into y=mx+b form. Then, the slope is just the 'm' term.

So, your slope is just the 'm' term, (the coefficient of x):

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Good Luck,
tutor_paul@yahoo.com
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
Think about a coordinate system. If a point is on the y-axis, what is its corresponding
x-value. You can see that any point on the y-axis has zero for its x-value.
.
Therefore for the given equation, if you set the value of x at zero, the resulting value of y
will be the value on the y-axis where the intercept occurs. So ... start with:
.
-x + 3y = 15
.
Set x equal to zero and the equation reduces to:
.
3y = 15
.
Solve for y by dividing both sides of this equation by 3 to get:
.
y = 15/3 = 5
.
The graph crosses the y-axis where the value of y is +5. You may also see the y intercept
given in the form of (x, y). So, from the discussion above, in this form the y-intercept
is expressed as (0, +5).
.
The graph of the given equation looks like this:
.

.
and you can see the y-intercept on this graph is at y = +5
.
Hope this helps you to understand the problem a little better.
.
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