SOLUTION: Solve the following system of linear inequalities by graphing.
3x + 4y < 12
x + 3y < 6
x > 0
y > 0
Hello,
I have no idea where to begin.
Thank you
Algebra.Com
Question 119868: Solve the following system of linear inequalities by graphing.
3x + 4y < 12
x + 3y < 6
x > 0
y > 0
Hello,
I have no idea where to begin.
Thank you
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
------------------
This means everything below (<)the line
------------------
This means everything below the line
------------------
You have to think about what the last two mean.
means is never negative or zero. That would be
everthing to the right of (0,0), the center of the graph
------------------
means everthing above (0,0)
When you put these two together, you get
the upper right quadrant of the graph
-----------------
The solution has to be above both lines and only in the
upper right quadrant. Here's the graph:
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