.
Find the slope-intercept form of the equation of the line passing through (-2,5)
perpendicular to the graph of y=-1/8x+19/4
~~~~~~~~~~~~~~~~
The line y = -1/8x+19/4 has the slope -1/8.
Hence, a perpendicular line has the slope of 8 (negative reciprocal to -1/8).
Thus the sough line has an equation
y - 5 = 8*(x-(-2)),
Simplify it
y - 5 = 8*(x+2)
y - 5 = 8x + 16
y = 8x + 21.
The last equation is in the slope-intercept form and is your ANSWER.
Solved and explained.
Read the lesson
- Equation for a straight line perpendicular to a given line and passing through a given point
in this site and find there the complete explanation on how to solve similar problems.
From this lesson, learn the subject once and for all.
-------------
At this site, there is a group of lessons related to this class of problems
- Find the slope of a straight line in a coordinate plane passing through two given points
- Equation for a straight line having a given slope and passing through a given point
- Solving problems related to the slope of a straight line
- Equation for a straight line in a coordinate plane passing through two given points
- Equation for a straight line parallel to a given line and passing through a given point
- Equation for a straight line perpendicular to a given line and passing through a given point (*)
- Advanced problems on finding equations for straight lines
The most relevant to your current problem is the lesson marked (*) in the list.
So start from this lesson.
But if you want to learn the subject in all its aspects, you need to learn all these lessons.
Consider them as your textbook, handbook, tutorials and (free of charge) home teacher.