SOLUTION: I think with this problem (t-7 over 4=11)you first multiply by 4 on both sides to get rid of it? But I'm not sure, can you please help me?
Algebra.Com
Question 119025This question is from textbook Alegebra one A
: I think with this problem (t-7 over 4=11)you first multiply by 4 on both sides to get rid of it? But I'm not sure, can you please help me?
This question is from textbook Alegebra one A
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I think with this problem (t-7 over 4=11)you first multiply by 4 on both sides to get rid of it? But I'm not sure, can you please help me?
:
Yes, that is the main step:
:
= 11
:
4* = 4(11)
:
t - 7 = 44
:
t = 7 + 44
:
t = 51
:
:
Check in original equation:
= 11
= 11
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
t-7 over 4=11
--------------
(t-7)/4 = 11
Multiply both sides by 4 to get:
t-7 = 44
Add 7 to both sides to get:
t = 51
===============
Cheers,
Stan H.
RELATED QUESTIONS
I think with this problem (t-7 over 4=11)you first multiply by 4 on both sides to get rid (answered by solver91311)
I am doing a multi-step equation with variables on both sides. I tried as far as I could... (answered by jim_thompson5910)
7 sq rt 100
_____________ (divided by)
sq rt 500
Do I multiply both sides by sq rt (answered by jim_thompson5910)
I need help with the following equation for all real numbers.... (answered by mananth)
Okay, here goes another easy one that I can't solve:
Printer A can print a report in 3... (answered by amnd)
Could you help with this problem:
1/3S + 7/9 = 4/3s
So far what I have done is:... (answered by stanbon)
{{{ log( 3,x ) }}} ^2 + {{{ log( 3,x^2) }}} -3 = 0
What is x?
Basically, this question (answered by josgarithmetic)
I have no idea of what to do with this problem. I tried mult both sides by 4 and also... (answered by tutorcecilia)
7x-2 divided by 10 = 9x divided by 4 + 6
I understand that I must get rid of the... (answered by ankor@dixie-net.com)