your equation is y = 7.25 * sin(30 * (x-7)) + 9.75
the graph of that is shown below.
the analysis was as follows:
the general form of the sine equation is y = a * sin(b * (x-c)) + d
a is the amplitude
b is the frequency
c is the horizontal displacement
d is the vertical displacement.
the high point of the wave was 17 and the low point of the wave was 2.5.
the difference was 17 minus 2.5 = 14.5
the amplitude is half of that = 7.25
that made a = 7.25
without any vertical displacement, the graph would go from -7.25 to 7.25
since you wanted the high point to be 17 and the low point to be 2.5, you needed to add 17 - 7.25 = 9.75 to the equation as vertical displacement.
the eqution became y = 7.25 * sin(b * (x - c)) + 9.75
there are 24 hours in a day.
since you needed to have two high points and two low point, then you need to have two full cycles of the sine wave in a 24 hour period.
that means one full cycle in a 12 hour period.
that';s your period.
frequency = 360 / period becomes frequency = 360 / 12 = 30.
that's your frequency.
the equation becomes y = 7.25 * sin(30 * (x - c)) + 9.75
without any horizontal displacement, the valur of y when x = 0 would be 9.75. and y = 17 at x = 3.
you 2want it to be at y = 17 when x = 10.
you need to shift the grsph 7 units to the right.
tht makes c = 7
the equation becomes y = 7.25 * sin(30 * (x - 7)) + 9.75
the horizontal shift was successful and now you have y = 17 at x = 10 and x = 22 (22 - 12 = 10 pm).
you also have y = 2.5 at x = 4 and x = 16 (16 - 12 = 10 pm)
i was using military time.
the am hours are as they are.
the pm hours are equal to what they are plus 12.
4 am = 4
10 am = 10
4 pm = 4 + 12 = 16
10 pm = 10 + 12 = 22
to find the height of the wave at 11:00 am, replace x with 11 to get:
y = 7.25 * sin(30 * (x = 7)) + 9.75 becomes:
y = 7.25 * sin(30 * (11 - 7)) + 9.75.
this makes y = 16.02868418 which rounds to y = 16.0.