y | |- 10 | |- 8 | |- 6 - 4 | |- 4 | |- 2 | ============ Populating the y-slots above or below the vertex, (- 6, - 4) gives us: ============ | x y | |- 10 12 | |- 8 0 | |- 6 - 4 | |- 4 | |- 2 | Below the VERTEX, we have the SAME y-coordinates we just found, ABOVE. This gives us:============ | x y | |- 10 12 | |- 8 0 | |- 6 - 4 | |- 4 0 | |- 2 12 | ============ You now have the vertex, (- 6, - 4), plus 2 points on EITHER side of the vertex. In addition, if you look you'll see the solutions to the quadratic: the points on the x-axis, or the roots, which are: - 8, from point (- 8, 0), and - 4, from the point, (- 4, 0)h, or x-coordinate of vertex occurs where k, or y-coordinate of vertex: With (h, k) being (- 6, 4), we get: ============ | x