SOLUTION: Three times the second of the consecutive even integers is 14 more than the sum of the first and the third. Find the middle integer.
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Question 118117: Three times the second of the consecutive even integers is 14 more than the sum of the first and the third. Find the middle integer.
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE 3 CONSECUTIVE EVEN NUMBERS.
3(X+2)=14+X+(X+4)
3X+6=14+2X+4
3X-2X=18-6
X=12 FOR THE FIRST EVEN NUMBER
12+2=14 FOR THE MIDDLE NUMBER
12+4=16 FOR THE LAST EVEN NUMBER
PROOF
3*14=14+12+16
42=42
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Three times the second of the consecutive even integers is 14 more than the sum of the first and the third. Find the middle integer.
-------------
1st = 2x
2nd = 2x+2
3rd = 2x+4
--------------
EQUATION:
3(2x+2)-14 =2x+2x+4
6x+6-14 = 4x+4
2x=12
x = 6
---------
2x+2 = 14
================
Cheers,
Stan H.
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