SOLUTION: Find the equation of the line perpendicular to y = 3x + 1 that passes through the point (9, -5). Give your answer in the form ax + by + c = 0
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Question 1180493: Find the equation of the line perpendicular to y = 3x + 1 that passes through the point (9, -5). Give your answer in the form ax + by + c = 0
Found 2 solutions by ankor@dixie-net.com, josgarithmetic:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find the equation of the line perpendicular to y = 3x + 1 that passes through the point (9, -5).
Perpendicular slope formula: m1*m2 = -1
m1 = 3 in our equation, find m2, the slope of the perpendicular line
3m2 = - 1
m2 = -1/3
m2 = -1/3 is the slope of the perpendicular line
let the points be
x1 = 9, y1 = -5, use point/slope equation y - y1 = m(x-x1)
y - (-5) = (x - 9)
y + 5 = x + 3
y = x + 3 - 5
y = x - 2, is the equation
Give your answer in the form ax + by + c = 0
We would like everything to be a positive integer, mult above by -3
-3y = x + 6
arrange it then as
x + 3y + 6 = 0 is this form
:
:
you can check this by replacing x with 9 and y with -5, see if equality reigns!
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Slope will need to be .
Using point-slope equation form, you want .
Simple algebra:
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